Beregn arealet mellom y=4−x2y=4-x^2y=4−x2 og xxx-aksen.
Klikk for å snu kortet
Skjæring med xxx-aksen: 4−x2=0⇒x=±24-x^2=0\Rightarrow x=\pm 24−x2=0⇒x=±2. Areal =∫−22(4−x2) dx=[4x−x33]−22=(8−83)−(−8+83)=323\displaystyle =\int_{-2}^{2}(4-x^2)\,dx = \left[4x - \frac{x^3}{3}\right]_{-2}^{2} = \left(8-\frac{8}{3}\right) - \left(-8+\frac{8}{3}\right) = \frac{32}{3}=∫−22(4−x2)dx=[4x−3x3]−22=(8−38)−(−8+38)=332.
Space / Enter for å snu